2[3lnx-ln(x+1)-ln(x-1)]=

Solution for 2[3lnx-ln(x+1)-ln(x-1)]= equation:

Simplifying
2[3lnx + -1ln(x + 1) + -1ln(x + -1)] = 0

Reorder the terms:
2[3lnx + -1ln(1 + x) + -1ln(x + -1)] = 0
2[3lnx + (1 * -1ln + x * -1ln) + -1ln(x + -1)] = 0
2[3lnx + (-1ln + -1lnx) + -1ln(x + -1)] = 0

Reorder the terms:
2[3lnx + -1ln + -1lnx + -1ln(-1 + x)] = 0
2[3lnx + -1ln + -1lnx + (-1 * -1ln + x * -1ln)] = 0
2[3lnx + -1ln + -1lnx + (1ln + -1lnx)] = 0

Reorder the terms:
2[-1ln + 1ln + 3lnx + -1lnx + -1lnx] = 0

Combine like terms: -1ln + 1ln = 0
2[0 + 3lnx + -1lnx + -1lnx] = 0
2[3lnx + -1lnx + -1lnx] = 0

Combine like terms: 3lnx + -1lnx = 2lnx
2[2lnx + -1lnx] = 0

Combine like terms: 2lnx + -1lnx = 1lnx
2[1lnx] = 0

Remove brackets around [1lnx]
2 * 1lnx = 0

Multiply 2 * 1
2lnx = 0

Solving
2lnx = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Divide each side by '2'.
lnx = 0

Simplifying
lnx = 0

The solution to this equation could not be determined.